x^4/3-7x^2/3+10=0

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Solution for x^4/3-7x^2/3+10=0 equation: 


x in (-oo:+oo)

(x^4)/3-((7*x^2)/3)+10 = 0

(x^4)/3+(-7/3)*x^2+10 = 0

1/3*x^4-7/3*x^2+10 = 0

t_1 = x^2

1/3*t_1^2-7/3*t_1^1+10 = 0

1/3*t_1^2-7/3*t_1+10 = 0

DELTA = (-7/3)^2-(1/3*4*10)

DELTA = -71/9

DELTA < 0

x belongs to the empty set

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